【leetcode】178. 分數排名

Create table If Not Exists Scores (Id int, Score DECIMAL(3,2))
Truncate table Scores
insert into Scores (Id, Score) values ('1', '3.5')
insert into Scores (Id, Score) values ('2', '3.65')
insert into Scores (Id, Score) values ('3', '4.0')
insert into Scores (Id, Score) values ('4', '3.85')
insert into Scores (Id, Score) values ('5', '4.0')
insert into Scores (Id, Score) values ('6', '3.65')

 

# Write your MySQL query statement below
select s1.Score, count(distinct s2.Score) Rank
from Scores as s1 join Scores as s2 on s1.Score <= s2.Score
group by s1.Id 
order by s1.Score DESC;