有這樣一個需求，對於各行數據要求 1+2 1+2+3 1+2+3+4 —– 2+3 2+3+4 —- 28+29
上面的1 2 3 是行號
我們以emp表爲例
WITH x0 AS
(SELECT rownum AS rn, sal FROM (SELECT sal FROM emp ORDER BY sal))
SELECT sal, dbms_aw.eval_number(substr(sys_connect_by_path(sal, '+'), 2))
FROM x0
CONNECT BY nocycle(PRIOR rn) = rn - 1
可以看下相加前的部分效果
800 800
950 800+950
1100 800+950+1100
1250 800+950+1100+1250
1250 800+950+1100+1250+1250
1300 800+950+1100+1250+1250+1300
1500 800+950+1100+1250+1250+1300+1500
1600 800+950+1100+1250+1250+1300+1500+1600
2450 800+950+1100+1250+1250+1300+1500+1600+2450
2850 800+950+1100+1250+1250+1300+1500+1600+2450+2850
2975 800+950+1100+1250+1250+1300+1500+1600+2450+2850+2975
3000 800+950+1100+1250+1250+1300+1500+1600+2450+2850+2975+3000
3000 800+950+1100+1250+1250+1300+1500+1600+2450+2850+2975+3000+3000
5000 800+950+1100+1250+1250+1300+1500+1600+2450+2850+2975+3000+3000+5000
950 950
1100 950+1100
1250 950+1100+1250
1250 950+1100+1250+1250
1300 950+1100+1250+1250+1300
1500 950+1100+1250+1250+1300+1500
SAL SUBSTR(SYS_CONNECT_BY_PATH(SAL