Sax解析xml遇到特殊字符問題

遇到問題:

sax解析xml時,遇到像<、>、&等特殊字符時,會把節點中的內容當做三段內容讀取,而我們原先的方式是隻做一次讀取,這樣會造成只能讀取到特殊字符前的內容。

解決方案:在解析時,做到把一個節點的內容讀完,才進行下一個節點的解析,充分利用startElement() 、endElement ()

上測試案例:

public class MyHandler extends DefaultHandler implements LexicalHandler {

        private StringBuffer str = null;
        @Override
        public void fatalError(SAXParseException e) throws SAXException {
        }

        @Override
        public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
            str = new StringBuffer();
        }

        @Override
        public void endElement(String uri, String localName, String qName) throws SAXException {
            super.endElement(uri, localName, qName);

        }

        @Override
        public void characters(char[] ch, int start, int length)
                throws SAXException {
            str.append(ch, start, length);  
        }

        @Override
        public void startEntity(String name) throws SAXException {
            
        }

        @Override
        public void endEntity(String name) throws SAXException {

        }

        @Override
        public void startDTD(String name, String publicId, String systemId)
                throws SAXException {
        }

        @Override
        public void endDTD() throws SAXException {
        }

        @Override
        public void startCDATA() throws SAXException {
        }

        @Override
        public void endCDATA() throws SAXException {
        }

        @Override
        public void comment(char[] ch, int start, int length) throws SAXException {
            // TODO Auto-generated method stub
            
        }
    }

調用:

final String ss = "<?xml version=\"1.0\" encoding=\"gbk\"?><data><url>http://192.168.33.194:8080/MobleTest/step3.jsp?app=test&amp;param=opps</url><title>百度</title></data>";  
                    SAXParserFactory saxparserfactory = SAXParserFactory.newInstance();  
                    SAXParser saxparser = saxparserfactory.newSAXParser();  
                    saxparser.parse(new java.io.ByteArrayInputStream(ss.getBytes()), new MyHandler()); 

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