Implicit intents with startService are not safe:解決辦法

有些時候我們使用Service的時需要採用隱私啓動的方式，但是Android 5.0一出來後，其中有個特性就是Service Intent  must be explitict，也就是說從Lollipop開始，service服務必須採用顯示方式啓動。

而android源碼是這樣寫的（源碼位置：sdk/sources/android-21/android/app/ContextImpl.java）：

private void validateServiceIntent(Intent service) {
       if (service.getComponent() == null && service.getPackage() == null) {
           if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {
               IllegalArgumentException ex = new IllegalArgumentException(
                       "Service Intent must be explicit: " + service);
               throw ex;
           } else {
               Log.w(TAG, "Implicit intents with startService are not safe: " + service
                       + " " + Debug.getCallers(2, 3));
           }
       }
   }

那麼這裏有兩種解決方法：

1、設置Action和packageName：

參考代碼如下：

Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");//你定義的service的action
mIntent.setPackage(getPackageName());//這裏你需要設置你應用的包名
context.startService(mIntent);

此方式是google官方推薦使用的解決方法。
在此附上地址供大家參考：http://developer.android.com/goo ... tml#billing-service,有興趣的可以去看看。

2、將隱式啓動轉換爲顯示啓動：--參考地址：http://stackoverflow.com/a/26318757/1446466

public static Intent getExplicitIntent(Context context, Intent implicitIntent) {
        // Retrieve all services that can match the given intent
        PackageManager pm = context.getPackageManager();
        List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);
        // Make sure only one match was found
        if (resolveInfo == null || resolveInfo.size() != 1) {
            return null;
        }
        // Get component info and create ComponentName
        ResolveInfo serviceInfo = resolveInfo.get(0);
        String packageName = serviceInfo.serviceInfo.packageName;
        String className = serviceInfo.serviceInfo.name;
        ComponentName component = new ComponentName(packageName, className);
        // Create a new intent. Use the old one for extras and such reuse
        Intent explicitIntent = new Intent(implicitIntent);
        // Set the component to be explicit
        explicitIntent.setComponent(component);
        return explicitIntent;
    }

調用方式如下：

Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");
Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));
context.startService(eintent);