JS遞歸調用定位ListView應該定位的項

繼續上篇的定位問題，由於時間原因，上篇的定位不是很準確，下面將準確定位的JS代碼共享出來：

function getIndexFromLab(lab)
    {
        var arr = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
        var j;
        for (j=0; j<arr.length; j++)
        {
            if (arr[j] === lab)
                break;
        }


        var i;
        for (i=0;i<list_model.count;i++)
        {
            if (list_model.get(i).sectionChar.substr(0, 1) === lab)
            {
                return i;
            }
        }
        if (i >= list_model.count)
        {
            return getIndexFromLab(arr[j-1]);
        }
    }

以上JS代碼，需要注意其遞歸調用處：return getIndexFromLab(arr[j-1]); 切記遞歸return，不熟悉遞歸的，這裏可能會犯錯。
調用定位處的代碼如下：
var idx = getIndexFromLab(modelData);
list_view.positionViewAtIndex(idx, ListView.Beginning);
然後將Repeater的model補全如下：
model: ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]

這樣，就能夠根據鼠標選中分組準確定位ListView了。