Oracle中一些和日期有关的SQL查询

1.判断某一天是周几 

select to_char(sysdate,'day') from dual; 

select to_char(to_date('2007-11-20','yyyy-mm-dd'),'day') from dual; 

2.求某月的天数 

select to_char(last_day(sysdate),'dd') days from dual; 

select to_char(last_day(to_date('200802','YYYYMM')),'dd') from dual; 

3.求某年的天数 

select add_months(trunc(sysdate,'year'), 12) - trunc(sysdate,'year') from dual; 

select add_months(trunc(to_date('2008','YYYY'),'year'), 12) - trunc(to_date('2008','YYYY'),'year') from dual; 

4.求下个星期一的日期 

在获取之前可以设置日期语言,如: 
ALTER SESSION SET NLS_DATE_LANGUAGE='SIMPLIFIED CHINESE'; 
select next_day(sysdate,'星期一') from dual; 
select next_day(sysdate,2) from dual; --后面的数字是从星期日开始算起,所以为2 

ALTER SESSION SET NLS_DATE_LANGUAGE='AMERICAN'; 
select next_day(sysdate,'monday') from dual; 

5.确定某天是当年的第几周 

select to_char(sysdate,'fmww') from dual; 

select to_char(to_date('20071126','YYYYMMDD'),'fmww') from dual; 


6.确定某天是当月的第几周 

select to_char(sysdate,'WW') - to_char(trunc(sysdate,'MM'),'WW') + 1 from dual 

select to_char(to_date('20071125','YYYYMMDD'),'WW') - to_char(trunc(to_date('20071125','YYYYMMDD'),'MM'),'WW') + 1 from dual 

7.确定某天是当年的第几天 

select to_char(sysdate,'DDD') from dual 

8.确定某天是当月的第几天 

select to_char(sysdate,'DD') from dual; 

9.确定某天是一周的第几天 

select to_char(sysdate,'D') - 1 from dual; --Oracle定义周日为一周的第一天,所以要减一 

10.求两个日期间的天数 

select floor(sysdate - to_date('20071125','YYYYMMDD')) from dual; 

11.求两个日期间的月数 

select floor(months_between(sysdate, to_date('20071031','YYYYMMDD'))) from dual; 

12.计算某天的小时、分、秒 

select day, 
TRUNC(a*24) Hours, 
TRUNC(a*24*60 - 60*TRUNC(a*24)) Minutes, 
TRUNC(a*24*60*60 - 60*TRUNC(a*24*60)) Seconds 
from ( select trunc(sysdate) day, sysdate - trunc(sysdate) a from dual);

 

 

按周按月:

 

select to_char(date,'ww'),count(id) from table group by to_char(date,'ww')

 

select to_char(date,'yyyymm'),count(id) from table group by to_char(date,'yyyymm')

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