gps座標離線轉百度座標

座標系簡介

WGS-84:是國際標準,GPS座標(Google Earth使用、或者GPS模塊)
GCJ-02:中國座標偏移標準,Google
Map、高德、騰訊使用 BD-09:百度座標偏移標準,Baidu Map使用

在線gps座標轉百度座標

在百度地圖中,如果直接給出gps座標,將造成偏差,需要將gps座標轉換成百度座標
如在百度地圖中給出gps座標(120.1755556, 35.94)
gps與實際偏差

在線轉換後的百度座標爲
在線轉換結果


離線gps轉百度地址

參考地址:http://bbs.lbsyun.baidu.com/forum.php?mod=viewthread&tid=10923
原文給出的代碼爲java,稍加修改爲C#代碼

測試結果

在給出代碼以前先給出測試結果

離線轉換結果

與在線轉換結果比較,小數點前4位爲爲精確,在民用中已經足夠

標註誤差


gps座標轉百度座標
相關文件下載:http://download.csdn.net/detail/u014124220/9645257


相關代碼

在線測試代碼

該效果測試html代碼,同時也包含在線座標轉換的方法

<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gp2312" />
<style type="text/css">
body, html,#allmap {width: 100%;height: 100%;overflow: hidden;margin:0;}
#l-map{height:100%;width:78%;float:left;border-right:2px solid #bcbcbc;}
#r-result{height:100%;width:20%;float:left;}
</style>
<script type="text/javascript" src="http://api.map.baidu.com/api?v=1.5&ak=9fb983ecd9b505f8fedcc9ab07c65e3e"></script>
<script type="text/javascript" src="http://developer.baidu.com/map/jsdemo/demo/convertor.js"></script>
<title>GPS轉百度</title>
</head>
<body>
<div id="allmap"></div>
</body>
</html>
<script type="text/javascript">
//GPS座標
var xx = 120.1755556;
var yy = 35.94;
var gpsPoint = new BMap.Point(xx,yy);

//地圖初始化
var bm = new BMap.Map("allmap");
bm.centerAndZoom(gpsPoint, 17);
bm.addControl(new BMap.NavigationControl());

//添加谷歌marker和label
var markergps = new BMap.Marker(gpsPoint);
bm.addOverlay(markergps); //添加GPS標註
var labelgps = new BMap.Label("我是GPS標註哦",{offset:new BMap.Size(20,-10)});
markergps.setLabel(labelgps); //添加GPS標註

//座標轉換完之後的回調函數
translateCallback = function (point){
    var marker = new BMap.Marker(point);
    bm.addOverlay(marker);
    var label = new BMap.Label("我是百度標註哦",{offset:new BMap.Size(20,-10)});
    marker.setLabel(label); //添加百度label
    bm.setCenter(point);
    alert("轉化爲百度座標爲:"+point.lng + "," + point.lat);
}

setTimeout(function(){
    BMap.Convertor.translate(gpsPoint,0,translateCallback);     //真實經緯度轉成百度座標
}, 2000);
</script>

————–離線代碼——————

java和C#代碼一併給出,相關變量如下

pi: 圓周率。 a: 衛星橢球座標投影到平面地圖座標系的投影因子。
ee: 橢球的偏心率。
x_pi: 圓周率轉換量。
transformLat(lat, lon): 轉換方法,比較複雜,不必深究了。輸入:橫縱座標,輸出:轉換後的橫座標。
transformLon(lat, lon): 轉換方法,同樣複雜,自行腦補吧。輸入:橫縱座標,輸出:轉換後的縱座標。
wgs2gcj(lat, lon): WGS座標轉換爲GCJ座標。 gcj2bd(lat, lon): GCJ座標轉換爲百度座標。

離線轉換 C#參考代碼

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace Mr_newbiebt
{
    class gps2bd
    {
        /*
         WGS-84:是國際標準,GPS座標(Google Earth使用、或者GPS模塊)
         GCJ-02:中國座標偏移標準,Google Map、高德、騰訊使用
         BD-09:百度座標偏移標準,Baidu Map使用

        代碼參考:http://bbs.lbsyun.baidu.com/forum.php?mod=viewthread&tid=10923
         */

        static double pi = 3.14159265358979324;
        static double a = 6378245.0;
        static double ee = 0.00669342162296594323;
        public const double x_pi = 3.14159265358979324 * 3000.0 / 180.0;

        /// <summary>
        /// gps座標轉換成百度座標,小數點前4位爲準確座標
        /// </summary>
        /// <param name="lat">緯度</param>
        /// <param name="lon">經度</param>
        /// <returns></returns>
        public static double[] wgs2bd(double lat, double lon)
        {
            double[] dwgs2gcj = wgs2gcj(lat, lon);
            double[] dgcj2bd = gcj2bd(dwgs2gcj[0], dwgs2gcj[1]);
            return dgcj2bd;
        }

        public static double[] gcj2bd(double lat, double lon)
        {
            double x = lon, y = lat;
            double z = Math.Sqrt(x * x + y * y) + 0.00002 * Math.Sin(y * x_pi);
            double theta = Math.Atan2(y, x) + 0.000003 * Math.Cos(x * x_pi);
            double bd_lon = z * Math.Cos(theta) + 0.0065;
            double bd_lat = z * Math.Sin(theta) + 0.006;
            return new double[] { bd_lat, bd_lon };
        }

        public static double[] bd2gcj(double lat, double lon)
        {
            double x = lon - 0.0065, y = lat - 0.006;
            double z = Math.Sqrt(x * x + y * y) - 0.00002 * Math.Sin(y * x_pi);
            double theta = Math.Atan2(y, x) - 0.000003 * Math.Cos(x * x_pi);
            double gg_lon = z * Math.Cos(theta);
            double gg_lat = z * Math.Sin(theta);
            return new double[] { gg_lat, gg_lon };
        }

        public static double[] wgs2gcj(double lat, double lon)
        {
            double dLat = transformLat(lon - 105.0, lat - 35.0);
            double dLon = transformLon(lon - 105.0, lat - 35.0);
            double radLat = lat / 180.0 * pi;
            double magic = Math.Sin(radLat);
            magic = 1 - ee * magic * magic;
            double sqrtMagic = Math.Sqrt(magic);
            dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
            dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
            double mgLat = lat + dLat;
            double mgLon = lon + dLon;
            double[] loc = { mgLat, mgLon };
            return loc;
        }

        private static double transformLat(double lat, double lon)
        {
            double ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.Sqrt(Math.Abs(lat));
            ret += (20.0 * Math.Sin(6.0 * lat * pi) + 20.0 * Math.Sin(2.0 * lat * pi)) * 2.0 / 3.0;
            ret += (20.0 * Math.Sin(lon * pi) + 40.0 * Math.Sin(lon / 3.0 * pi)) * 2.0 / 3.0;
            ret += (160.0 * Math.Sin(lon / 12.0 * pi) + 320 * Math.Sin(lon * pi / 30.0)) * 2.0 / 3.0;
            return ret;
        }

        private static double transformLon(double lat, double lon)
        {
            double ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.Sqrt(Math.Abs(lat));
            ret += (20.0 * Math.Sin(6.0 * lat * pi) + 20.0 * Math.Sin(2.0 * lat * pi)) * 2.0 / 3.0;
            ret += (20.0 * Math.Sin(lat * pi) + 40.0 * Math.Sin(lat / 3.0 * pi)) * 2.0 / 3.0;
            ret += (150.0 * Math.Sin(lat / 12.0 * pi) + 300.0 * Math.Sin(lat / 30.0 * pi)) * 2.0 / 3.0;
            return ret;
        }
    }
}

離線轉換 java參考代碼

static double pi = 3.14159265358979324;
static double a = 6378245.0;
static double ee = 0.00669342162296594323;
public final static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;

public static double[] wgs2bd(double lat, double lon) {
       double[] wgs2gcj = wgs2gcj(lat, lon);
       double[] gcj2bd = gcj2bd(wgs2gcj[0], wgs2gcj[1]);
       return gcj2bd;
}

public static double[] gcj2bd(double lat, double lon) {
       double x = lon, y = lat;
       double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);
       double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);
       double bd_lon = z * Math.cos(theta) + 0.0065;
       double bd_lat = z * Math.sin(theta) + 0.006;
       return new double[] { bd_lat, bd_lon };
}

public static double[] bd2gcj(double lat, double lon) {
       double x = lon - 0.0065, y = lat - 0.006;
       double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);
       double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);
       double gg_lon = z * Math.cos(theta);
       double gg_lat = z * Math.sin(theta);
       return new double[] { gg_lat, gg_lon };
}

public static double[] wgs2gcj(double lat, double lon) {
       double dLat = transformLat(lon - 105.0, lat - 35.0);
       double dLon = transformLon(lon - 105.0, lat - 35.0);
       double radLat = lat / 180.0 * pi;
       double magic = Math.sin(radLat);
       magic = 1 - ee * magic * magic;
       double sqrtMagic = Math.sqrt(magic);
       dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
       dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);
       double mgLat = lat + dLat;
       double mgLon = lon + dLon;
       double[] loc = { mgLat, mgLon };
       return loc;
}

private static double transformLat(double lat, double lon) {
       double ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.sqrt(Math.abs(lat));
       ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
       ret += (20.0 * Math.sin(lon * pi) + 40.0 * Math.sin(lon / 3.0 * pi)) * 2.0 / 3.0;
       ret += (160.0 * Math.sin(lon / 12.0 * pi) + 320 * Math.sin(lon * pi  / 30.0)) * 2.0 / 3.0;
       return ret;
}

private static double transformLon(double lat, double lon) {
       double ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.sqrt(Math.abs(lat));
       ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
       ret += (20.0 * Math.sin(lat * pi) + 40.0 * Math.sin(lat / 3.0 * pi)) * 2.0 / 3.0;
       ret += (150.0 * Math.sin(lat / 12.0 * pi) + 300.0 * Math.sin(lat / 30.0 * pi)) * 2.0 / 3.0;
       return ret;
}
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