with cte as( select bianma,fjbm from #tree where chkDisabled='true' union all select t.bianma,t.fjbm from cte c inner join #tree t on c.fjbm=t.bianma ) select * from cte;
with cte as( select bianma,fjbm from #tree where chkDisabled='true' union all select t.bianma,t.fjbm from cte c inner join #tree t on c.fjbm=t.bianma ) select * from cte;
根據提示,賦權限,刪除文件等 jimmy@MacBook-Pro ~ % brew link node Linking /usr/local/Cellar/node/20.0.0... Er
# 假設puzzle是一個包含多個字符串的列表,每個字符串都是同一長度的,代表字母網格的一行 puzzle = [ "JGJGDDAOYD", "IDGFHSPOSA", "FGDIOSAFSC