辣雞劉的Leetcode之旅5(SQL Part)【誰沒點餐，】

1. Customers Who Never Order
   題目描述：

Suppose that a website contains two tables, the Customers table and the Orders table. Write a SQL query to find all customers who never order anything.

Table: Customers.

+----+-------+
| Id | Name  |
+----+-------+
| 1  | Joe   |
| 2  | Henry |
| 3  | Sam   |
| 4  | Max   |
+----+-------+
Table: Orders.

+----+------------+
| Id | CustomerId |
+----+------------+
| 1  | 3          |
| 2  | 1          |
+----+------------+
Using the above tables as example, return the following:

+-----------+
| Customers |
+-----------+
| Henry     |
| Max       |
+-----------+

這個其實和上面的一個題是類似的，只不過有取反的意思：下面是我做的：

Select Name as Customers from Customers c 
where not exists (Select CustomerId from Orders o where o.CustomerId=c.Id);

再看看大神的：

select Name as 'Customers' from Customers where id not in (select CustomerId from orders)

直接看ID，很可以。
其他三種：

SELECT A.Name from Customers A
WHERE NOT EXISTS (SELECT 1 FROM Orders B WHERE A.Id = B.CustomerId)

SELECT A.Name from Customers A
LEFT JOIN Orders B on  a.Id = B.CustomerId
WHERE b.CustomerId is NULL

SELECT A.Name from Customers A
WHERE A.Id NOT IN (SELECT B.CustomerId from Orders B)