九度1500

/*
nlgn lis 的簡單題

*/
#include
#include
#include
using namespace std;

const int maxn = 1000000 + 10;

int data[maxn], lis[maxn], l[maxn], r[maxn];

int Find(int x, int r){
	int ans = 0, l = 1;
	while(l <= r){
		int mid = (l + r) >> 1;
		if(lis[mid] < x){
			ans = mid;
			l = mid + 1;
		}
		else r = mid - 1;
	}
	return ans;
}


int main(){
    //freopen("in","r",stdin);
	int n;
	while(scanf("%d",&n) != EOF){
		for(int i = 1 ;i <= n; ++ i){
			scanf("%d",&data[i]);
		}
		int now = 1;
		lis[now] = data[now];
		l[1] = 1;
		for(int i = 2 ;i <= n; ++ i){
			if(data[i] > lis[now]){
				lis[++ now] = data[i];
				l[i] = now;
			}
			else {
				int cur = Find(data[i],now);
				if(lis[cur + 1] > data[i])	lis[cur + 1] = data[i];
				l[i] = cur + 1;
			}
		}
		r[n] = 1;
		now = 1;
		lis[now] = data[n];
		for(int i = n - 1 ;i >= 1 ; -- i){
			if(data[i] > lis[now]) {
				lis[++now] = data[i];
				r[i] = now;
			}
			else{
                int cur= Find(data[i],now);
                if(lis[cur+ 1] > data[i]) lis[cur+ 1] = data[i];
                r[i] = cur + 1;
			}


		}
		int ans = 0;

		for(int i = 1 ;i <= n; ++ i){
			ans = max(l[i] + r[i] - 1, ans);
		}
		ans = n - ans;
		printf("%d\n",ans);

	}
	return 0;
}