協助開發導入庫時,他提醒我,庫裏有存儲過程的定義。我使用了--routines 的選項,可是導入時,出了問題:
1.提示無法創建該存儲過程,原來是忘了打開 log_bin_trust_function_creators 變量,
set global log_bin_trust_function_creators=on; 後,成功創建,從服務器也需要此操作
才行,如果二進制日誌是 ROW 的話,即使從上有此存儲過程,也是不會調用的。
2.等到導入成功後,卻又出現了無法調用的問題,搜索了 http://www.2cto.com/database/201403/288436.html 這篇文章,記錄下此問題。
創建一個 definer 爲 user_admin 的存儲過程
mysql> DELIMITER // mysql> CREATE DEFINER='user_admin' PROCEDURE num1() -> BEGIN -> SELECT COUNT(id) FROM itopserver; -> END // Query OK, 0 rows affected, 1 warning (0.00 sec) mysql> DELIMITER ;
2. 創建一個用戶,並賦於其 相關權限
mysql> create user user_itop identified by '123456'; Query OK, 0 rows affected (0.00 sec) mysql> grant select,insert,delete,update on itop.* to 'user_test'@'%'; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_test@'%'; +---------------------------------------------------------------------+ | Grants for user_test@% | +---------------------------------------------------------------------+ | GRANT USAGE ON *.* TO 'user_test'@'%' | | GRANT SELECT, INSERT, UPDATE, DELETE ON `itop`.* TO 'user_test'@'%' | +---------------------------------------------------------------------+ 2 rows in set (0.00 sec)
3. 使用 user_test 連接 mysql 並執行剛纔創建的 procedure
mysql> call num1; ERROR 1370 (42000): execute command denied to user 'user_test'@'%' for routine 'itop.num1'
4. 這樣看是權限的問題,因爲只給了他操作表的方法。 增加其 itop 的 execute 權限
mysql> grant execute on itop.* to user_test@'%'; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_test@'%'; +----------------------------------------------------------------------------------------------------------+ | Grants for user_test@% | +----------------------------------------------------------------------------------------------------------+ | GRANT USAGE ON *.* TO 'user_test'@'%' IDENTIFIED BY PASSWORD '*6BB4837EB74329105EE4568DDA7DC67ED2CA2AD9' | | GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `itop`.* TO 'user_test'@'%' | +----------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)
5. 重新使用此用戶連接 Mysql 執行剛纔定義的存儲過程
mysql> use itop; mysql> call num1(); ERROR 1449 (HY000): The user specified as a definer ('user_admin'@'%') does not exist
現在可以調用該存儲過程了,但是提示存儲過程定義中的definer不存在,
原來僅僅是連接到MySQL服務器的用戶具有執行存儲過程的權限是遠遠不夠的,
最終要通過存儲過程定義中指定的definer來執行存儲過程。
6. 說 user_admin 不存在,那就創建 user_admin 這個用戶
mysql> grant select,insert,delete,update on itop.* to 'user_admin'@'%' identified by '123456'; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_admin@'%'; +-----------------------------------------------------------------------------------------------------------+ | Grants for user_admin@% | +-----------------------------------------------------------------------------------------------------------+ | GRANT USAGE ON *.* TO 'user_admin'@'%' IDENTIFIED BY PASSWORD '*6BB4837EB74329105EE4568DDA7DC67ED2CA2AD9' | | GRANT SELECT, INSERT, UPDATE, DELETE ON `itop`.* TO 'user_admin'@'%' | +-----------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)
7. 重新使用 "user_test" 用戶連接 Mysql 執行剛纔定義的存儲過程
mysql> use itop; mysql> call num1(); ERROR 1370 (42000): execute command denied to user 'user_admin'@'%' for routine 'itop.num1'
8. 看來不僅僅是連接到MySQL服務器的用戶需要具有存儲過程上的執行權限,存儲過程定義者同樣需要該權限。
mysql> grant execute on itop.* to 'user_admin'@'%'; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_admin; +-----------------------------------------------------------------------------------------------------------+ | Grants for user_admin@% | +-----------------------------------------------------------------------------------------------------------+ | GRANT USAGE ON *.* TO 'user_admin'@'%' IDENTIFIED BY PASSWORD '*6BB4837EB74329105EE4568DDA7DC67ED2CA2AD9' | | GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `itop`.* TO 'user_admin'@'%' | +-----------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)
9. 重新使用 "user_test" 用戶連接 Mysql 執行剛纔定義的存儲過程
mysql> use itop; mysql> call num1(); +-----------+ | COUNT(id) | +-----------+ | 372 | +-----------+ 1 row in set (0.00 sec) Query OK, 0 rows affected (0.00 sec)
可以執行了