算法分析與設計第九周作業

算法分析與設計第九周作業


題目

t a lemonade stand, each lemonade costs $5.

Customers are standing in a queue to buy from you, and order one at a time (in the order specified by bills).

Each customer will only buy one lemonade and pay with either a $5, $10, or $20 bill. You must provide the correct change to each customer, so that the net transaction is that the customer pays $5.

Note that you don’t have any change in hand at first.

Return true if and only if you can provide every customer with correct change.
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解答

很簡單的貪心算法,只用先給大的,再給小的就可以了。

class Solution {
public:
    bool lemonadeChange(vector<int>& bills) {
        unsigned five_cash_cnt = 0;
        unsigned ten_cash_cnt = 0;

        for (const int bill : bills)
        {
            switch (bill)
            {
                case 5:
                    five_cash_cnt++;
                    break;
                case 10:
                    if (!five_cash_cnt)
                    {
                        return false;
                    }
                    five_cash_cnt--;
                    ten_cash_cnt++;
                    break;
                case 20:
                    if (ten_cash_cnt && five_cash_cnt)
                    {
                        ten_cash_cnt--;
                        five_cash_cnt--;
                    }
                    else if (five_cash_cnt > 2)
                    {
                        five_cash_cnt -= 3;
                    }
                    else
                    {
                        return false;
                    }
                    break;
            }
        }
        return true;
    }
};

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