下標從1開始遍歷數組,使用一個max變量來記錄最大的差值。差值使用Math.abs來計算
奉上java滿分代碼
import java.util.*;
public class Main{
public static void main(String[] args){
Scanner scanner = new Scanner(System.in);
int n = Integer.parseInt(scanner.nextLine());
int[] numbers = new int[n];
String[] line = scanner.nextLine().split(" ");
for(int i = 0; i < n; i++){
numbers[i] = Integer.parseInt(line[i]);
}
scanner.close();
int max = 0;
for(int i = 1; i < n; i++){
int minus = Math.abs(numbers[i] - numbers[i - 1]);
if(minus > max)
max = minus;
}
System.out.println(max);
}
}