# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def buildTree(self, inorder, postorder):
"""
:type inorder: List[int]
:type postorder: List[int]
:rtype: TreeNode
"""
if postorer is not:
return None
root = TreeNode(postorer[-1])
n = inorder.index(root.val)
root.left = self.buildTree(inorder[:n], postorder[:n])
root.right = self.buildTree(inorder[n+1:], postorder[n:-1])
return root
106. 從中序與後序遍歷序列構造二叉樹
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