Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward.
Example 1:
Input: 121
Output: true
Example 2:
Input: -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Follow up:
Coud you solve it without converting the integer to a string?
注:直接用栈和队列做的,时间复杂度有点大。Runtime: 120 ms, faster than 48.36% of C online submissions for Palindrome Number. 等有时间再想想好的办法。
bool isPalindrome(int x) {
//声明栈和队列
int stack[100];
int top = 0;
int que[100];
int rear = 0,front = 0;
int temp;
if(x < 0)
return false;
while(x > 0){
que[++rear] = x%10;
stack[++top] = x%10;
x = x/10;
}
int j = top;
for(int i = 0; i < j; ++i){
if(que[++front] != stack[top--]){
return false;
}
}
return true;
}