給定一個未排序的數組,判斷這個數組中是否存在長度爲 3 的遞增子序列。
數學表達式如下:
如果存在這樣的 i, j, k, 且滿足 0 ≤ i < j < k ≤ n-1,
使得 arr[i] < arr[j] < arr[k] ,返回 true ; 否則返回 false 。
說明: 要求算法的時間複雜度爲 O(n),空間複雜度爲 O(1) 。
示例 1:
輸入: [1,2,3,4,5]
輸出: true
示例 2:
輸入: [5,4,3,2,1]
輸出: false
// start with two largest values, as soon as we find a number bigger than both, while both have been updated, return true.
public boolean increasingTriplet(int[] nums) {
int small = Integer.MAX_VALUE, big = Integer.MAX_VALUE;
for (int n : nums) {
if (n <= small) { small = n; } // update small if n is smaller than both
else if (n <= big) { big = n; } // update big only if greater than small but smaller than big
else return true; // return if you find a number bigger than both
}
return false;
}