C#實現二進制轉10進制

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;


namespace 二轉十
{
    class Program
    {
        /// <summary>
        /// 求次方
        /// </summary>
        /// <param name="number">那個數的次方</param>
        /// <param name="cifang">幾次方</param>
        /// <returns>number^cifang</returns>
        static int CiFang(int number,int cifang)
        {
            int returnValue = 0; // 返回值
            if (number == 0) // 0的次方都是0
            {
                return returnValue;
            }
            if (cifang == 0) // 任何數的0次方都是1
            {
                returnValue = 1;
                return returnValue;
            }
            if (cifang == 1) // 任何數的1次方都是任何數
            {
                returnValue = number;
                return returnValue;
            }


            returnValue = number;
            // 
            for (int i = 1; i < cifang; i++)
            {
                //次方
                returnValue *= number;
            }
            //返回最終結果
            return returnValue;
        }


        static void Main(string[] args)
        {
        


            int[] randomInts = new int[5];
            Random r = new Random();
            for (int i = 0; i < randomInts.Length; i++)
            {
                randomInts[i] = r.Next(0, 2);
            }
            //遍歷
            foreach (int i in randomInts)
            {
                Console.Write(i);
            }
            Console.WriteLine();
            Console.WriteLine("====================");
            //弄一個10個數值 0~1
            int number = 0;
            //使用按位展開法逆向得出10進制
            for (int i = 0; i < randomInts.Length; i++)
            {
                //1. 獲取一個二進制位


               // if (randomInts[i] == 0)
               // {
               //     number += CiFang(0, randomInts.Length - 1 - i);
               // }
               //else
               // {
               //     number += CiFang(2, randomInts.Length - 1 - i);


               // }
                number += CiFang((randomInts[i] == 0) ? 0 : 2, randomInts.Length - 1 - i);


                // 2. 得知是N次方


            }
          Console.WriteLine(number);
        }
    }
}