【LeetCode】Algorithm 51～60：58

前言

本系列博客爲平時刷LeetCode的記錄，每十道題一篇博客，持續更新，所有代碼詳見GitHub：https://github.com/roguesir/LeetCode-Algorithm

58. Length of Last Word

Introduce

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:

Input: "Hello World"
Output: 5

Solution

class Solution(object):
    def lengthOfLastWord(self, s):
        """
        :type s: str
        :rtype: int
        """
        return len(s.strip().split(" ")[-1])

https://leetcode.com/submissions/detail/202036869/

• 更新時間：2019-02-27