问题描述
农夫需要把狼、羊、菜和自己运到河对岸去,只有农夫能够划船,而且船比较小,除农夫之外每次只能运一种东西,还有一个棘手的问题,就是如果没有农夫看着,羊会偷吃菜,狼会吃羊。请考虑一种方法,让农夫能够安全地安排这些东西和他自己过河。
代码实现
本题使用深度优先策略构建行动树,搭配三种剪枝逻辑以保证结果可行
老婆饿了,要赶回家送饭,细节请读代码,见谅~~
left = 0b1111
right = 0b0000
steps = [0b1000, 0b1001, 0b1010, 0b1100]
wrong = [0b0110, 0b0011]
ever = [right]
path = []
def search_path(left, right, ever, path):
if right == 0b1111:
print(path)
return
for step in steps:
if max(left, right) & step != step:
continue
left_n = left ^ step
right_n = right ^ step
if left_n in wrong or right_n in wrong:
continue
if right_n in ever:
continue
path_n = path[:]
path_n.append(step)
ever_n = ever[:]
ever_n.append(right_n)
search_path(left_n, right_n, ever_n, path_n)
search_path(left, right, ever, path)