Introduction
Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123
Output: 321
Example 2:
Input: -123
Output: -321
Example 3:
Input: 120
Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
Solution
class Solution(object):
def reverse(self, x):
"""
:type x: int
:rtype: int
"""
x = str(x)
y = ""
if x[0] == "-":
y = y + x[0]
for i in range(len(x)-1, 0, -1):
y += x[i]
else:
for i in range(len(x)-1, -1, -1):
y += x[i]
if int(y) > 2**31-1 or int(y) < -2**31:
return 0
else:
return int(y)
Code
GitHub:https://github.com/roguesir/LeetCode-Algorithm
- 更新時間:2019-03-01