【镜像二叉树】Python解法

利用递归，可以完美解决镜像二叉树问题，对于每个节点的左子树和右子树，进行交换即可

# -*- coding:utf-8 -*-
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
class Solution:
    # 返回镜像树的根节点
    def Mirror(self, root):
        # write code here
        if root:
            root.left, root.right = root.right, root.left
            self.Mirror(root.left)
            self.Mirror(root.right)