LeetCode--No.1041--Robert Bounded in Circle

On an infinite plane, a robot initially stands at (0, 0) and faces north.  The robot can receive one of three instructions:

  • "G": go straight 1 unit;
  • "L": turn 90 degrees to the left;
  • "R": turn 90 degress to the right.

The robot performs the instructions given in order, and repeats them forever.

Return true if and only if there exists a circle in the plane such that the robot never leaves the circle.

 

Example 1:

Input: "GGLLGG"
Output: true
Explanation: 
The robot moves from (0,0) to (0,2), turns 180 degrees, and then returns to (0,0).
When repeating these instructions, the robot remains in the circle of radius 2 centered at the origin.

Example 2:

Input: "GG"
Output: false
Explanation: 
The robot moves north indefinetely.

Example 3:

Input: "GL"
Output: true
Explanation: 
The robot moves from (0, 0) -> (0, 1) -> (-1, 1) -> (-1, 0) -> (0, 0) -> ...

 

Note:

  1. 1 <= instructions.length <= 100
  2. instructions[i] is in {'G', 'L', 'R'}

 

第一次參加競賽。 2019/05/11 10:30pm 有點意思

新題果然都是看起來很難的

一共四道題,只做出來一道easy, 排名1790/4109, 提交了3次錯誤答案。
丟人啊哈哈哈,那道題就不粘出來了。第二道題提交了1次,錯了。
後來過了時間,改對了
代碼寫的是真的難看

題目真的不難,思路完全有,並且沒什麼問題。
只是數組多了就亂了,不簡潔,寫起來小錯誤就會更多,變量名隨便亂起,自己都不知道該用什麼。

數組下標從0開始,與題目裏面設計的index對應不上,想不清楚什麼時候該減1,什麼時候不動。

自己跑test case能力很弱,test case設計不好,corner case考慮不到,這些都是問題。
總體上說,思路不夠清晰。其實這兩道題都很簡單,都應該是一次A過 bug free的那一種。
看來改變coding的習慣還是要時刻注意。加油~!希望下週至少能順利A出來兩道題吧。
 

class Solution {
    public int[] gardenNoAdj(int N, int[][] paths) {
        int[] res = new int[N];
        if (paths == null || paths.length == 0 || paths[0].length == 0){
            for(int i = 0; i < N; i++){
                res[i] = 1;
            }
            return res;
        }
        Map<Integer, int[]> map = new HashMap<>();
        for(int[] path: paths){
            int min = Math.min(path[0], path[1]);
            int max = Math.max(path[0], path[1]);
            if (map.containsKey(max)){
                int[] tmp = map.get(max);
                if (tmp[1] == -1)   tmp[1] = min;
                else   tmp[2] = min;
                map.put(max, tmp);
            }
            else{
                int[] tmp = new int[3];
                tmp[0] = min;
                tmp[1] = -1;
                tmp[2] = -1;
                map.put(max, tmp);
            }
        }

        res[0] = 1;
        for(int i = 1; i < N; i++){
            if (!map.containsKey(i+1))
                res[i] = 1;
            else{
                int[] tmp = map.get(i+1);
                int[] tmp2 = new int[4];
                for(int k = 0; k < 4; k++)
                    tmp2[k] = 0;
                
                if (tmp[0] != -1)   tmp2[res[tmp[0] - 1]-1] = 1;
                if (tmp[1] != -1)   tmp2[res[tmp[1] - 1]-1] = 1;
                if (tmp[2] != -1)   tmp2[res[tmp[2] - 1]-1] = 1;

                if (tmp2[0] == 0)   res[i] = 1;
                else if (tmp2[1] == 0)  res[i] = 2;
                else if (tmp2[2] == 0)  res[i] = 3;
                else res[i] = 4;
            }
        }
        return res;
    }
}

 

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