SQL: XPath for sql

DECLARE @XML XML
SET @XML= '
<basevendors>
    <basevendor name="Northeast" taxid="99999" description="Re/Max Northeast" activevendor="Y" apvendornumber="8888">
        <basevendorcontactinfo>
            <basevendoraddress addressline1="2940 Oak St." City="Kingwood" statecode="TX" zip="77339" country="USA" effectivedate="11/11/2001" />
            <basevendoraddress addressline1="1849 Kingwood Dr." City="Kingwood" statecode="TX" zip="0" country="USA" />
        </basevendorcontactinfo>
    </basevendor>
    <basevendor name="Better Homes &amp; Gardens Rand Realty" taxid="321456" description="Better Homes &amp; Gardens Rand Realty" activevendor="Y" apvendornumber="87542">
        <basevendorcontactinfo>
            <basevendoraddress addressline1="10 Schriever Lane" City="New City" statecode="NY" zip="10956" country="USA" effectivedate="11/22/1899" />
        </basevendorcontactinfo>
    </basevendor>
    <basevendor name="Bodell-Van Drimmelen" taxid="9856587" description="Bodell-Van Drimmelen" activevendor="N" apvendornumber="22545">
        <basevendorcontactinfo>
            <basevendoraddress addressline1="Residential Appraisers, Inc." City="Salt Lake City" statecode="UT" zip="84106" country="USA" effectivedate="04/29/2003"/>
            <basevendoraddress addressline1="Residential Appraisers, Inc." City="Salt Lake City" statecode="UT" zip="0" country="USA" effectivedate="04/11/2003" />
        </basevendorcontactinfo>
    </basevendor>
    <basevendor name="Rental Relocation Inc." taxid="6589654" description="Rental Relocation Inc." activevendor="Y" apvendornumber="778855" />
</basevendors>'

SELECT Vendor.value('@name[1]','varchar(50)') AS VendorName, Vendor.value('@taxid[1]','varchar(50)') AS TaxID
    , addr.value('@addressline1[1]','varchar(200)') AS AddressLine, addr.value('@City[1]','varchar(10)') AS City
FROM @XML.nodes('basevendors/basevendor') BV(Vendor)
CROSS APPLY BV.Vendor.nodes('basevendorcontactinfo/basevendoraddress') addrs(addr)

 

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