前段时间在工作中遇到需要一对多关联查询的情况,百度了好久遇到各种坑,所以在此记录一下,话不多说直接开始
首先,先建几个测试类,主子表通过grade_id关联,具体属性注释我就省略不写了,大家能看懂
@Data
@TableName("grade")
public class Grade implements Serializable {
private Long id;
private String name;
private String address;
}
子表1@Data
@TableName("teacher")
public class Teacher implements Serializable {
private Long id;
private String name;
private Integer age;
private String categroy;
private Integer level;
private Long gradeId; // 关联主表id
}
子表2@Data
@TableName("student")
public class Student implements Serializable {
private Long id;
private String name;
private Integer age;
private String address;
private Long gradeId; // 关联主表id
}
表结构和实体类一样我就不放了,没啥特别的
其次,创建一个DTO用来接收查询出来的结果,这个大家都懂,不解释
@Data
public class GradeDTO implements Serializable {
private Long id;
private String name;
private String address;
private List<Teacher> teacherList;
private List<Student> studentList;
}
重点,配置mapper.xml文件
首先需要配置resultMap用来接收返回结果,这个大家百度得到,关联集合就是用collection,如下 <resultMap type="com.kasi.mybatis_plus.model.GradeDTO" id="gradeMap">
<id column="id" property="id"/>
<result column="name" property="name"/>
<result column="address" property="address"/>
<collection property="teacherList" ofType="com.kasi.mybatis_plus.model.Teacher" >
<id column="t_id" property="id"/>
<result column="t_name" property="name"/>
<result column="t_age" property="age"/>
<result column="t_categroy" property="categroy"/>
<result column="t_level" property="level"/>
</collection>
<collection property="studentList" ofType="com.kasi.mybatis_plus.model.Student">
<id column="s_id" property="id"/>
<result column="s_name" property="name"/>
<result column="s_age" property="age"/>
<result column="s_address" property="address"/>
</collection>
</resultMap>
常用的属性就不说了,特别要注意的是ofType这个要指向各自表的实体类,然后子表的column属性不要和主表重名,一旦重名就会出问题,不知道是不是我配置的问题,希望有大佬指教,反正不重名就可以
接下来就是查询语句了,很简单,只要别名和上面resultMap对的上就ok <select id="get" resultMap="gradeMap">
SELECT
a.id,
a.name,
a.address,
b.id as t_id,
b.name as t_name,
b.age as t_age,
b.categroy as t_categroy,
b.level as t_level,
c.id as s_id,
c.name as s_name,
c.age as s_age,
c.address as s_address
FROM grade a
LEFT JOIN teacher b ON a.id=b.grade_id
LEFT JOIN student c ON a.id=c.grade_id
WHERE a.id=#{id}
</select>
最后,看看查询结果,其实很简单的,网上教程也很多,但是别名那个地方很多人都没有强调导致犯了很多错
ps:查询集合也是一样的,不说了
数据表查询
实际查询结果{
"id": 1,
"name": "3年1班",
"address": "三楼",
"teacherList": [
{
"id": 1,
"name": "宋元桥",
"age": 50,
"categroy": "武当",
"level": 1,
"gradeId": null
},
{
"id": 2,
"name": "俞莲舟",
"age": 43,
"categroy": "武当",
"level": 2,
"gradeId": null
}
],
"studentList": [
{
"id": 1,
"name": "金毛狮王",
"age": 47,
"address": "冰火岛",
"gradeId": null
},
{
"id": 2,
"name": "紫衫龙王",
"age": 39,
"address": "灵蛇岛",
"gradeId": null
}
]
}