用Collections.sort方法對list排序有兩種方法
第一種是list中的對象實現Comparable接口,如下:
/**
* 根據order對User排序
*/
public class User implements Comparable<User>{
private String name;
private Integer order;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Integer getOrder() {
return order;
}
public void setOrder(Integer order) {
this.order = order;
}
public int compareTo(User arg0) {
return this.getOrder().compareTo(arg0.getOrder());
}
} 測試一下:
public class Test{
public static void main(String[] args) {
User user1 = new User();
user1.setName("a");
user1.setOrder(1);
User user2 = new User();
user2.setName("b");
user2.setOrder(2);
List<User> list = new ArrayList<User>();
//此處add user2再add user1
list.add(user2);
list.add(user1);
Collections.sort(list);
for(User u : list){
System.out.println(u.getName());
}
}
}
輸出結果如下
a
b
第二種方法
根據Collections.sort重載方法來實現,例如:
//根據order對User排序
public class User { //此處無需實現Comparable接口
private String name;
private Integer order;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Integer getOrder() {
return order;
}
public void setOrder(Integer order) {
this.order = order;
}
}
主類中這樣寫即可(HastSet——>List——>sort進行排序):
public class Test {
public static void main(String[] args) {
User user1 = new User();
user1.setName("a");
user1.setPrice(11);
User user2 = new User();
user2.setName("b");
user2.setPrice(2);
Set<User> Hset = new HashSet<User>();
Hset.add(user2);
Hset.add(user1);
List<User> list = new ArrayList<User>();
list.addAll(Hset);
Collections.sort(list,new Comparator<User>(){
public int compare(User arg0, User arg1) {
return arg0.getPrice().compareTo(arg1.getPrice());
}
});
for(User u : list){
System.out.println(u.getName());
}
}
輸出結果如下:
a
b
默認爲升序,將。return arg0.getOrder().compareTo(arg1.getOrder()); 改爲:
return arg1.getOrder().compareTo(arg0.getOrder());
就成降序的了。