Oracle练习题（1）
1. 查询工资大于12000的员工姓名和工资
select last_name, salary
from employees
where salary > 12000
2. 查询员工号为176的员工的姓名和部门号
select last_name, department_id
from employees
where employee_id = 176
3. 选择工资不在5000到12000的员工的姓名和工资
select last_name, salary
from employees
where salary not between 5000 and 12000
4. 选择雇用时间在1998-02-01到1998-05-01之间的员工姓名，job_id和雇用时间
select last_name, job_id, hire_date
from employees
where hire_date between '1-2月 -1998' and '1-5月 -1998'
5. 选择在20或50号部门工作的员工姓名和部门号
select last_name, department_id
from employees
where department_id in (20, 50)
6. 选择在1994年雇用的员工的姓名和雇用时间
select last_name, hire_date
from employees
where hire_date like '% -94'
7. 选择公司中没有管理者的员工姓名及job_id
select last_name, job_id
from employees
where manager_id is null
8. 选择公司中有奖金的员工姓名，工资和奖金级别
select last_name, salary, commission_pct
from employees
where commission_pct is not null
9. 选择员工姓名的第三个字母是a的员工姓名
select last_name
from employees
where last_name like '__a%'
10. 选择姓名中有字母a和e的员工姓名
select last_name
from employees
where last_name like '%a%' and last_name like '%e%'
11. 显示系统时间
select to_char(sysdate, 'yyyy-mm-dd hh:mi:ss') from dual;
12. 查询员工号，姓名，工资，以及工资提高百分之20%后的结果（new salary）
select employee_id, last_name, salary, salary * 1.2 "new salary"
from employees;
13. 将员工的姓名按首字母排序，并写出姓名的长度（length）
select last_name, length(last_name)
from employees
order by last_name
14. 查询各员工的姓名，并显示出各员工在公司工作的月份数（worked_month）。
select last_name, months_between(sysdate, hire_date) worked_month
from employees
15. 查询员工的姓名，以及在公司工作的月份数（worked_month），并按月份数降序排列
select last_name, months_between(sysdate, hire_date) worked_month
from employees
order by worked_month desc
16. 做一个查询，产生下面的结果
<last_name> earns monthly but wants <salary*3>
| Dream Salary |
|---|
| King earns $24000 monthly but wants $72000 |
select last_name || ' earns ' || salary || ' monthly but wants ' || salary * 3
from employees
17. 使用decode函数，按照下面的条件：
job grade
AD_PRES A
ST_MAN B
IT_PROG C
SA_REP D
ST_CLERK E
Others F
产生下面的结果
| Last_name | Job_id | Grade |
|---|---|---|
| king | AD_PRES | A |
select last_name, job_id, decode(job_id, 'AD_PRES', 'A',
'ST_MAN', 'B',
'IT_PROG', 'C',
'SA_REP', 'D',
'ST_CLERK', 'E',
'F') GRADE
from employees
18. 将第7题的查询用case函数再写一遍。
select last_name, job_id, case job_id when 'AD_PRES' then 'A'
when 'ST_MAN' then 'B'
when 'IT_PROG' then 'C'
when 'SA_REP' then 'D'
when 'ST_CLERK' then 'E'
else 'F'
end
from employees
19. 查询公司员工工资的最大值，最小值，平均值，总和
Select max(salary), min(salary), avg(salary), sum(salary)
From employees
20. 查询各job_id的员工工资的最大值，最小值，平均值，总和
Select job_id, max(salary), min(salary), avg(salary), sum(salary)
From employees
Group by job_id
21. 选择具有各个job_id的员工人数
Select job_id, count(employee_id)
From employees
Group by job_id;
22. 查询员工最高工资和最低工资的差距（DIFFERENCE）
Select max(salary) – min(salary) difference
From employees
23. 查询各个管理者手下员工的最低工资，其中最低工资不能低于6000，没有管理者的员工不计算在内
Select manager_id, min(salary)
From employees
Where manager_id is not null
Group by manager_id
Having min(salary) >= 6000
24. 查询所有部门的名字，location_id，员工数量和工资平均值
Select department_name, location_id, count(employee_id), avg(salary)
From employees e join departments d
On e.department_id = d.department_id
Group by department_name, location_id