LeetCode 1114. Print in Order--C++,Python解法

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LeetCode題解專欄：LeetCode題解
我做的所有的LeetCode的題目都放在這個專欄裏，大部分題目Java和Python的解法都有。

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題目地址：Print in Order - LeetCode

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Suppose we have a class:

public class Foo {
  public void first() { print("first"); }
  public void second() { print("second"); }
  public void third() { print("third"); }
}

The same instance of Foo will be passed to three different threads. Thread A will call first(), thread B will call second(), and thread C will call third(). Design a mechanism and modify the program to ensure that second() is executed after first(), and third() is executed after second().

Example 1:

Input: [1,2,3]
Output: "firstsecondthird"
Explanation: There are three threads being fired asynchronously. The input [1,2,3] means thread A calls first(), thread B calls second(), and thread C calls third(). "firstsecondthird" is the correct output.

Example 2:

Input: [1,3,2]
Output: "firstsecondthird"
Explanation: The input [1,3,2] means thread A calls first(), thread B calls third(), and thread C calls second(). "firstsecondthird" is the correct output.
 

Note:

We do not know how the threads will be scheduled in the operating system, even though the numbers in the input seems to imply the ordering. The input format you see is mainly to ensure our tests’ comprehensiveness.

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這道題目的意思是進程調度

Python解法如下：

import time
class Foo:
    def __init__(self):
        self.flag=0
        

    def first(self, printFirst: 'Callable[[], None]') -> None:
        
        # printFirst() outputs "first". Do not change or remove this line.
        printFirst()
        self.flag=1

    def second(self, printSecond: 'Callable[[], None]') -> None:
        while self.flag!=1:
            time.sleep(0.01)
        # printSecond() outputs "second". Do not change or remove this line.
        printSecond()
        self.flag=2


    def third(self, printThird: 'Callable[[], None]') -> None:
        while self.flag!=2:
            time.sleep(0.01)
        # printThird() outputs "third". Do not change or remove this line.
        printThird()
        self.flag=3

C++解法如下：