BigDecimal問題

https://blog.csdn.net/haiyinshushe/article/details/82721234 舍入解讀 ROUND_UP

截圖說的是 創建最好用String

 

 

public class BigDecimalTest {
    private BigDecimal num1=new BigDecimal(0.005);
    private BigDecimal str1=new BigDecimal("0.005");
    private BigDecimal num2=new BigDecimal(1000000);
    private BigDecimal str2=new BigDecimal("1000000");
    @Test
    public void test(){
        BigDecimal addNum = num1.add(num2);
        BigDecimal addStr = str1.add(str2);
        BigDecimal subNum = num1.subtract(num2);
        BigDecimal subStr = str1.subtract(str2);
        System.out.println("addNum::::::"+addNum);
        System.out.println("addStr::::::"+addStr);
        System.out.println("subNum::::::"+subNum);
        System.out.println("subStr::::::"+subStr);
        //除法
        BigDecimal result = num2.divide(num1,20,BigDecimal.ROUND_HALF_UP);
        BigDecimal resultS = str2.divide(str1,20,BigDecimal.ROUND_HALF_UP);
        System.out.println("result:::::"+result);
        System.out.println("resultS::::"+resultS);
    }
}

addNum::::::1000000.005000000000000000104083408558608425664715468883514404296875
addStr::::::1000000.005
subNum::::::-999999.994999999999999999895916591441391574335284531116485595703125
subStr::::::-999999.995
result:::::199999999.99999999583666365766
resultS::::200000000.00000000000000000000