sql查詢範例1.1

Student(S#,Sname,Sage,Ssex) 學生表
Course(C#,Cname,T#) 課程表
SC(S#,C#,score) 成績表
Teacher(T#,Tname) 教師表

問題:
1、查詢“001”課程比“002”課程成績高的所有學生的學號;
 
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
 
from SC where C#='002') b
 
where a.score>b.score and a.s#=b.s#;
2、查詢平均成績大於60分的同學的學號和平均成績;
   
select S#,avg(score)
   
from sc
   
group by S# having avg(score) >60;
3、查詢所有同學的學號、姓名、選課數、總成績;
 
select Student.S#,Student.Sname,count(SC.C#),sum(score)
 
from Student left Outer join SC on Student.S#=SC.S#
 
group by Student.S#,Sname
4、查詢姓“李”的老師的個數;
 
select count(distinct(Tname))
 
from Teacher
 
where Tname like '李%';
5、查詢沒學過“葉平”老師課的同學的學號、姓名;
   
select Student.S#,Student.Sname
   
from Student 
   
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where  SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平');
6、查詢學過“001”並且也學過編號“002”課程的同學的學號、姓名;
 
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、查詢學過“葉平”老師所教的所有課的同學的學號、姓名;
 
select S#,Sname
 
from Student
 
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher  where Teacher.T#=Course.T# and Tname='葉平'));
8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;
 
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
 
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score;
9、查詢所有課程成績小於60分的同學的學號、姓名;
 
select S#,Sname
 
from Student
 
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查詢沒有學全所有課的同學的學號、姓名;
   
select Student.S#,Student.Sname
   
from Student,SC
   
where Student.S#=SC.S# group by  Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查詢至少有一門課與學號爲“1001”的同學所學相同的同學的學號和姓名;
   
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、查詢至少學過學號爲“001”同學所有一門課的其他同學學號和姓名;
   
select distinct SC.S#,Sname
   
from Student,SC
   
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把“SC”表中“葉平”老師教的課的成績都更改爲此課程的平均成績;
   
update SC set score=(select avg(SC_2.score)
   
from SC SC_2
   
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');
14、查詢和“1002”號的同學學習的課程完全相同的其他同學學號和姓名;
   
select S# from SC where C# in (select C# from SC where S#='1002')
   
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、刪除學習“葉平”老師課的SC表記錄;
    Delect SC
   
from course ,Teacher 
   
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';
16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號“003”課程的同學學號、2
    號課的平均成績;
   
Insert SC select S#,'002',(Select avg(score)
   
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、按平均成績從高到低顯示所有學生的“數據庫”、“企業管理”、“英語”三門的課程成績,按如下形式顯示: 學生ID,,數據庫,企業管理,英語,有效課程數,有效平均分
   
SELECT S# as 學生ID
        ,(
SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 數據庫
        ,(
SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理
        ,(
SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語
        ,
COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績
   
FROM SC AS t
   
GROUP BY S#
   
ORDER BY avg(t.score) 
18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分
   
SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分
   
FROM SC L ,SC AS R
   
WHERE L.C# = R.C# and
        L.score
= (SELECT MAX(IL.score)
                     
FROM SC AS IL,Student AS IM
                     
WHERE L.C# = IL.C# and IM.S#=IL.S#
                     
GROUP BY IL.C#)
       
AND
        R.Score
= (SELECT MIN(IR.score)
                     
FROM SC AS IR
                     
WHERE R.C# = IR.C#
                 
GROUP BY IR.C#
                    );
19、按各科平均成績從低到高和及格率的百分數從高到低順序
   
SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績
        ,
100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數
   
FROM SC T,Course
   
where t.C#=course.C#
   
GROUP BY t.C#
   
ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理(001),馬克思(002),OO&UML (003),數據庫(004
   
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分
        ,
100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數
        ,
SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分
        ,
100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數
        ,
SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
        ,
100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數
        ,
SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 數據庫平均分
        ,
100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 數據庫及格百分數
 
FROM SC

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