LintCode-劍指Offer-(376)二叉樹路徑求和

/**
 * Definition of TreeNode:
 * class TreeNode {
 * public:
 *     int val;
 *     TreeNode *left, *right;
 *     TreeNode(int val) {
 *         this->val = val;
 *         this->left = this->right = NULL;
 *     }
 * }
 */
class Solution {
public:
    /**
    * @param root the root of binary tree
    * @param target an integer
    * @return all valid paths
    */
    vector<vector<int>> binaryTreePathSum(TreeNode *root,int& target) {
        // Write your code here
        vector<vector<int>> t;
        vector<int> tmp;
        GetPath(root,0,target,tmp,t);
        return t;
    }
    void GetPath(TreeNode* node,int sumbefore,int target,
        vector<int>& vecpart,vector<vector<int>>& vecall){
        if (node==NULL){
            return;
        }
        if (node->val+sumbefore==target){
            vecpart.push_back(node->val);
            vecall.push_back(vecpart);
            return;
        }
        else {
            vecpart.push_back(node->val);
            vector<int> t1=vecpart;
            vector<int> t2 = vecpart;
            GetPath(node->left,node->val+sumbefore,target,t1,vecall);
            GetPath(node->right,node->val+sumbefore,target,t2,vecall);
        }
    }
};