182. Duplicate Emails#2

Solutin#1

SELECT Email FROM (
SELECT Email, COUNT(Email) AS Cnt FROM Person GROUP BY Email
) T WHERE Cnt > 1

Solutin#2()

SELECT Email FROM Person GROUP BY Email HAVING COUNT(Email) > 1

Problem
1. Mysql：Windows表名不區分大小寫，Linux區分；字段都不區分大小寫
2. 子查詢臨時表必須有別名
3. WHERE 和 HAVING區別