網頁製作工程中會經常遇見數據的傳輸。然而對於java或者php等是在服務器執行的程序，當頁面加載之後嵌在html的這些代碼是最先執行的。所以利用簡單的傳遞數據是有問題的。現在介紹幾種不同的傳遞參數問題。
1、利用JS傳遞
這裏利用表單的post，在表單裏面加一個隱藏表單元素比如： <input type="hidden" style="" readonly="true" />
只需要把值傳給value就，接下來就簡單了。
2、主要寫一下怎麼用Ajax傳數據到java服務器（對於php也是靈活改動即可）
Ajax可以使網頁實現異步更新。這意味着可以在不重新加載整個網頁的情況下，對網頁的某部分進行更新。Ajax的功能很強大，值得去研究。
直接代碼解釋吧
html頁面代碼。index.jsp
<%@ page import="java.sql.*"%>
<%@ page language="java" import="java.util.*" contentType="text/html; charset=UTF-8" %>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>AJAX calls using Jquery in Servlet</title>
<script type="text/javascript" src="./js/jquery.min.js"></script>
<script>
$(document).ready(function() {
$('#submit').click(function(event) {
var username=$('#user').val();
$.get('ActionServlet',{user:username},
function(responseText) {
$('#welcometext').text(responseText);
});
});
});
</script>
</head>
<body>
<form id="form1">
<h1>AJAX Demo using Jquery in JSP and Servlet</h1>
Enter your Name:
<input type="text" id="user"/>
<input type="button" id="submit" value="Ajax Submit"/>
<br/>
<div id="welcometext">
</div>
</form>
</body>
</html>這是Ajax核心代碼，代碼很簡單，稍微一看就會明白：
<script type="text/javascript" src="./js/jquery.min.js"></script>
<script>
$(document).ready(function() {
$('#submit').click(function(event) {
var username=$('#user').val();
$.get('ActionServlet',{user:username},
function(responseText) {
$('#welcometext').text(responseText);
});
});
});
</script>這是主要的代碼片段。代碼很簡單，很容易看懂，是通過get的方法直接傳入到後臺java。
命名：ActionServlet.javapackage ajaxdemo;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class ActionServlet
*/
public class ActionServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public ActionServlet() {
// TODO Auto-generated constructor stub
}
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String name=null;
name = "Hello "+request.getParameter("user");
if(request.getParameter("user").toString().equals("")){
name="Hello User";
}
response.setContentType("text/plain");
response.setCharacterEncoding("UTF-8");
response.getWriter().write(name);
//System.out.println(name);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
}
}
對於jsp需要更改一下web.xml。在web-app標籤裏面加入下面代碼,注意路徑的準確性
<servlet>
<servlet-name>ActionServlet</servlet-name>
<servlet-class>ajaxdemo.ActionServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ActionServlet</servlet-name>
<url-pattern>/ActionServlet/*</url-pattern>
</servlet-mapping>轉載：（有改動）
http://www.programming-free.com/2012/08/ajax-with-jsp-and-servlet-using-jquery.html
