hdu 1712 ACboy needs your help

Problem Description

ACboy has N courses this term, and he plans to spend at most M days on study.Of course,the profit he will gain from different course depending on the days he spend on it.How to arrange the M days for the N courses to maximize the profit?

 

Input

The input consists of multiple data sets. A data set starts with a line containing two positive integers N and M, N is the number of courses, M is the days ACboy has.
Next follow a matrix A[i][j], (1<=i<=N<=100,1<=j<=M<=100).A[i][j] indicates if ACboy spend j days on ith course he will get profit of value A[i][j].
N = 0 and M = 0 ends the input.

 

Output

For each data set, your program should output a line which contains the number of the max profit ACboy will gain.

 

Sample Input

2 2 1 2 1 3 2 2 2 1 2 1 2 3 3 2 1 3 2 1 0 0

 

Sample Output

3 4 6

 

Source

HDU 2007-Spring Programming Contest

 

簡單的分組揹包：

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std; 
int a[105][105],dp[105];
int main()
{
	int n,m,i,j,k;
	while(~scanf("%d%d",&n,&m)&&(n||m))
	{
		for(i=1;i<=n;i++)
		for(j=1;j<=m;j++)
		scanf("%d",&a[i][j]);
		memset(dp,0,sizeof(dp));
		for(i=1;i<=n;i++)
		{
			for(j=m;j>0;j--)
			{
				for(k=1;k<=m;k++)
				{
					if(j>=k) 
					dp[j]=max(dp[j],dp[j-k]+a[i][k]);
				}
			}
		}
		printf("%d\n",dp[m]);
	}
}