在shell開發中,會遇到將10以內的數字前面加0的情況,例如按小時分區執行hive腳本,具體代碼如下:
#!/bin/sh
START_DAY=$1
END_DAY=$2
FLAG_DAY=${START_DAY}
START_HOUR=$3
END_HOUR=$4
executeHive() {
while :
do
local STAT_HOUR=00
local FLAG_HOUR=23
local START_DAY=$(date -d "$START_DAY 1day" +%Y%m%d)
local STAT_DAY=`date -d "${START_DAY} -1 day" +%Y%m%d`
# 判斷執行日期是否爲開始日期或結束日期
if [ ${STAT_DAY} -eq ${FLAG_DAY} ]; then
STAT_HOUR=${START_HOUR}
elif [ ${STAT_DAY} -eq ${END_DAY} ]; then
FLAG_HOUR=${END_HOUR}
fi
while :
do
printf "[INFO] `date '+%F %T'` current execute partition is dt=${STAT_DAY} hour=${STAT_HOUR}\n"
exitCode=$?
if [ $exitCode -ne 0 ];then
printf "[ERROR] `date '+%F %T'` hivesql execute ${SOL_FILE} is failed!!!\n"
exit $exitCode
else
printf "[INFO] `date '+%F %T'` hivesql ${STAT_DAY} ${STAT_HOUR} data execute success!!!\n"
fi
# 因爲小時小於10時前面有0,shell腳本會認爲是八進制數字,所以要轉爲十進制數字
#STAT_HOUR=$((10#$STAT_HOUR+1))
STAT_HOUR=$(($STAT_HOUR+1))
# 判斷小時是否小於10
if [ ${STAT_HOUR} -lt 10 ]; then
STAT_HOUR=0${STAT_HOUR}
fi
# 如果執行小時大於設置的結束小時,退出循環
if [ ${STAT_HOUR} -gt ${FLAG_HOUR} ]; then
break;
fi
done
# 判斷執行日期是否等於結束日期,等於則退出循環
if [ ${STAT_DAY} -eq ${END_DAY} ]; then
break;
fi
done
}
if [ ${START_DAY} -gt ${END_DAY} ]; then
printf "[ERROR] `date '+%F %T'` --start-day:${START_DAY} greater than --end-day:${END_DAY}\n"
exit 1
elif [ ${START_HOUR} -ge 24 ] || [ ${START_HOUR} -lt 0 ] || [ ${END_HOUR} -ge 24 ] || [ ${END_HOUR} -lt 0 ]; then
printf "[ERROR] `date '+%F %T'` --start-hour:${START_DAY} or --end-hour:${END_DAY} is not 00-23 \n"
exit 1
else
executeHive
printf "[INFO] `date '+%F %T'` hivesql ${START_DAY} to ${END_DAY} data execute success!!!\n"
fi
當執行命令:sh houeTest.sh 20200202 20200203 19 23
會報如下錯誤:
houeTest.sh: line 38: 08: value too great for base (error token is "08")
解決方法:將代碼第38行改爲第37行
STAT_HOUR=$(($STAT_HOUR+1))
改爲:STAT_HOUR=$((10#$STAT_HOUR+1))
就不會報錯了