A+B
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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3674 Accepted Submission(s): 2098
現在請計算A+B的結果,並以正常形式輸出。
#include<cstdio>
#include<cstring>
#include<cmath>
#include<cstdlib>
#include<algorithm>
using namespace std;
typedef long long int LL;
char s1[15];
char s2[15];
LL fun(char *s)
{
LL sum=0;
int len=strlen(s);
for(int i=0;i<len;i++)
if(s[i]>='0'&&s[i]<='9')
sum=sum*10+s[i]-'0';
return sum;
}
int main()
{
while(~scanf("%s %s",s1,s2))
{
LL x=fun(s1);
LL y=fun(s2);
if(s1[0]=='-')
x=-x;
if(s2[0]=='-')
y=-y;
printf("%lld\n",x+y);
}
return 0;
}