mysql实现同一张表内，统计不同条件的数据

想要同时统计bug表的激活bug数量，与已完成bug数量。
SELECT p.name ‘所属项目’, COUNT(b.status) ‘激活状态BUG总数’
FROM zt_bug b ,zt_project p WHERE b.project IN (464,465,466) AND p.id=b.project AND b.status=’active’
GROUP BY project;

SELECT p.name ‘所属项目’, COUNT(b.status) ‘已解决状态BUG总数’
FROM zt_bug b ,zt_project p WHERE b.project IN (464,465,466) AND p.id=b.project AND b.status=’resolved’
GROUP BY project;

失败的尝试：
SELECT p.name ‘所属项目’,COUNT(b.status = ‘active’) ‘激活状态安全BUG总数’,COUNT(b.status = ‘resolved’) ‘已解决状态安全BUG总数’
FROM zt_bug b,zt_project p
WHERE b.project IN (464, 465, 466)
AND p.id = b.project
GROUP BY project ;

解决方法:
mysql提供if函数，可以在查询是使用。
SELECT p.name ‘所属项目’,
SUM(
IF((b.status=’active’),1,0)
) ‘激活状态安全BUG总数’,
SUM(
IF((b.status=’resolved’),1,0)
) ‘已解决状态安全BUG总数’
FROM zt_bug b ,zt_project p WHERE b.project IN (464,465,466) AND p.id=b.project
GROUP BY project;