先來個大栗子:
# Description: Simple smtp test
# Author: xumesang
# Date: 2016-11-7
import smtplib
from email.mime.text import MIMEText
mailto_list = "[email protected]"
mail_host = "smtp.163.com"
mail_user = "yyy"
mail_password = "zzz"
mail_postfix = "163.com"
def send_mail(to_list, sub, content):
me = "zm" + "<" + mail_user + "@" + mail_postfix + ">"
msg = MIMEText(content, _subtype = 'plain', _charset = 'gb2312')
msg['Subject'] = sub
msg['From'] = me
msg['to'] = ";".join(to_list)
try:
server = smtplib.SMTP()
server.connect(mail_host)
server.login(mail_user, mail_password)
server.sendmail(me, to_list, msg.as_string())
server.close()
return True
except Exception, e:
print str(e)
return False
if __name__ == '__main__':
if send_mail(mailto_list, "zm", "Hello M, Please contact me immediately when you see this email."):
print "Success"
else:
print "Fail"
本實例已經經過測試,只需填寫適當郵件參數即可。
在測試的過程中如果遇到問題,可以根據下面網易提供的返回結果判斷錯誤原因:
http://help.163.com/09/1224/17/5RAJ4LMH00753VB8.html