Problem:
Given an integer array of size n,
find all elements that appear more than ⌊ n/3 ⌋
times.
The algorithm should run in linear time and in O(1) space.
Analysis:
Use Boyer-Moore voting algorithm (https://en.wikipedia.org/wiki/Boyer%E2%80%93Moore_majority_vote_algorithm ) , and then test the candidate elements are eligible for majority elements.
Solutions:
C++:
vector<int> majorityElement(vector<int>& nums) {
vector<int> results;
if(nums.empty())
return results;
if(nums.size() == 1) {
results.push_back(nums[0]);
return results;
}
int first = 0, second = 0, f_count = 0, s_count = 0;
for(int i = 0; i < nums.size(); ++i) {
if(f_count == 0) {
first = nums[i];
++f_count;
} else if(nums[i] == first) {
++f_count;
}else if(s_count == 0) {
second = nums[i];
++s_count;
} else if(nums[i] == second) {
++s_count;
} else {
--f_count;
--s_count;
}
}
f_count = 0;
s_count = 0;
for(int i = 0; i < nums.size(); ++i) {
if(nums[i] == first)
++f_count;
else if(nums[i] == second)
++s_count;
}
if(f_count > nums.size() / 3)
results.push_back(first);
if(s_count > nums.size() / 3)
results.push_back(second);
}
Java:
Python: