codility MaxCounters

Question:codility Lesson4 MaxCounters

My answer:

def solution(N,A):
    res = [0] * N

    maxnum = 0
    curmax = 0

    for com in A:
        if 1 <= com <= N:
            if maxnum > res[com - 1]:
                res[com -1] = maxnum
            res[com - 1] += 1
            if curmax < res[com - 1]:
                curmax = res[com - 1]
        else:
            maxnum = curmax

    for i in range(0,N):
        if res[i] < maxnum:
            res[i] = maxnum

    return res