php獲取跳轉後的網址，使用curl

方法1：

$url = 'http://www.baidu.com/link?url=77I2GJqjJ4zBBpC8yDF8xDhiqDSn1JZjFWsHhEoSNd85PkV8Xil-rckpQ8_kjGKNNq';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_NOBODY, 1);// 不需要頁面內容
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);// 不直接輸出
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);// 返回最後的Location
curl_exec($ch);
$info = curl_getinfo($ch,CURLINFO_EFFECTIVE_URL);
curl_close($ch);
echo $info;

 方法2：

1. $ch=  curl_init("http://www.baidu.com");
2. curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
3. curl_setopt($ch, CURLOPT_AUTOREFERER, 1);
4. curl_setopt($ch, CURLOPT_NOBODY, 1);
5. curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
6. curl_setopt($ch, CURLOPT_HEADER, 1);
7. curl_exec($ch);
8. $aaa = curl_getinfo($ch, CURLINFO_EFFECTIVE_URL);
9. echo $aaa;