想到了算法之一
# this function is used to move all odd number to front part of an array and even numbers end.
def test(arr)
endix = arr.size-1
arr.each_with_index do |v,i|
if i >= endix
return
end
if v % 2 == 0 # met a even
# swap this even with the last odd
until arr[endix] % 2 == 1 or endix <= i
endix -= 1
end
arr[i],arr[endix]=arr[endix],arr[i]
end
end
end
時間複雜度是O(n),空間複雜度是O(1).