題解:
1.將StringBuffer str轉換爲string str,用contains函數判斷是否存在空格
2.若沒有空格,直接輸出string str
3.否則將string str轉換爲字符串型判斷空格位置,在空格處使用str.replace(i,i+1,"%20"),輸出獲得的字符串
import javax.swing.*;
import java.util.*;
import java.lang.*;
class Solution {
public String replaceSpace(StringBuffer str) {
int a=0;
String x="";
if(str.toString().contains(" "))
for (int i = 0; i < (str.toString().toCharArray()).length; i++)
{ if ((str.toString().toCharArray())[i] == ' ')
str.replace(i,i+1,"%20");
if(i==(str.toString().toCharArray()).length-1)
{ a=1;
x= str.toString();
}
}
// System.out.println(x);
if(a==0)
return str.toString();
else
return x;
}
}
public class Main {
public static void main(String[] args){
Scanner input=new Scanner(System.in);
StringBuffer x=new StringBuffer(input.nextLine());
Solution Solution =new Solution();
Solution.replaceSpace(x);
}
}