題目:替換空格---請實現一個函數,把字符串中的每個空格替換成“%20”
<span style="font-size:18px;">#include<iostream>
using namespace std;
void ReplaceBlack(char str[],int len)
{
if (str == NULL || len <= 0)
{
return;
}
int i = 0;
int relLen = 0;//str的真實長度
int numOfBlack = 0; // 空格的個數
while (str[i] != '\0')
{
if (str[i] == ' ')
{
++numOfBlack;
}
relLen++;
++i;
}
int _len = relLen + 2 * numOfBlack;//替換後的總長度
while (relLen < _len && relLen > 0)
{
//1.當字符不等於' '時,就往後挪字符
//2.當字符等於' '時,就去添加%20
if (str[relLen] != ' ')
{
str[_len--] = str[relLen];
}
else
{
str[_len--] = '0';
str[_len--] = '2';
str[_len--] = '%';
}
relLen--;
}
}
int main()
{
char str[30] = { "We are happy." };
ReplaceBlack(str, sizeof(str));
cout << str << endl;
return 0;
}</span>
結果如下圖2: