9. Fizz Buzz 問題

Note

兩段代碼都能達到13ms以上，網速夠好的情況下。只有一點要記住，必須先判斷能否同時被3和5整除。

class Solution {
public:
    /**
     * @param n: An integer
     * @return: A list of strings.
     */
    vector<string> fizzBuzz(int n) {
        vector<string> vecstr;
        for (int i = 1; i <= n; ++i)
        {
            int a = i % 10;
            if (i % 3 == 0)
            {
                if (a == 0 || a == 5)
                    vecstr.push_back("fizz buzz");
                else
                    vecstr.push_back("fizz");
            }
            else if (a == 0 || a == 5)
                vecstr.push_back("buzz");
            else
                vecstr.push_back(to_string(i));
        }
        return vecstr;
    }
};

class Solution {
public:
    /**
     * @param n: An integer
     * @return: A list of strings.
     */
    vector<string> fizzBuzz(int n) {
        vector<string> vecstr;
        for (int i = 1; i <= n; ++i)
        {
            if (i % 3 == 0 && i % 5 == 0)
                vecstr.push_back("fizz buzz");
            else if (i % 3 == 0)
                vecstr.push_back("fizz");
            else if (i % 5 == 0)
                vecstr.push_back("buzz");
            else
                vecstr.push_back(to_string(i));
        }
        return vecstr;
    }
};