問題:某商店規定,三個空汽水瓶可以換一瓶汽水。小王手上有十個空汽水瓶,他最多可以換多少瓶汽水,答案是5瓶,方法如下:先用9個空瓶子換3瓶,喝掉這3瓶之後,剩4個空瓶子,再用3瓶去換一瓶,喝完剩2個空瓶子,這時可以向老闆借一瓶,喝掉這瓶滿的,剩3個空瓶,換一瓶滿的還給老闆,如果小王手裏有n個空瓶,問最多可以換多少瓶汽水喝?
import java.util.Scanner;
class Main {
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int s=0;
int h=0;
int count=0;
if (n != 0 && n <= 100) {
while (n >= 3) {
h = n / 3;
s = n % 3;
n = s + h;
count = count + h;
}
}
if(n==2){
count=count+1;
}
System.out.println(count);
}
}