发表于2008年08月02日 12:46 阅读(8) 评论(0)
1.select
SELECT * FROM chinese ;
SELECT name as 姓名 FROM chinese ;
SELECT * FROM chinese c where age between 18 and 30;
SELECT * FROM test1 t where realist = false and interesting is not null;
SELECT * FROM test1 t where realist = false or interesting is not null;
SELECT * FROM chinese c where name like '%黄%' order by name asc; //升序
SELECT * FROM chinese c where name like '%黄%' order by name desc; //%任意字符串
SELECT * FROM chinese c where phone like '55_' order by name desc; //_任一字符
SELECT count(*) as '记录数' FROM chinese c; //计下有几条记录
SELECT count(age) as 'ageNO' FROM chinese c; //计下记录中age不为空的数目
SELECT sum(age) as '全部人总年龄' FROM chinese c; //求age字段的值总和
SELECT avg(age) as '平均年龄' FROM chinese c; //总和 / !非空值!记录数
SELECT max(age) as '最大年龄' FROM chinese c;
SELECT min(age) as '最小年龄' FROM chinese c;
2.insert
insert into test2 (name,phone) values ('zhaozhao','13222445566');
3.update
update test3 set phone = '13912345678' where name = 'zhaozhao1'
4.delete
delete from test3 where phone = '13912345678' //删除记录集 ,系"集"
delete from test3 //删除表中所有记录
5.drop
drop table test3 //删除表
6.create
create table test3 ( UserId char(5),name char(20),phone char(20),Userright boolean,primary key(UserId) )
//primary key 定义主键