HDU 1175(搜索DFS)

#include <stdio.h>
#include <string.h>
#include <iostream>
using namespace std;
int ss[1005][1005];
int vis[1005][1005];
int dir[4][2] = {1, 0, -1, 0, 0, 1, 0, -1};
int x1, y1, x2, y2, n, m;
int fi;
int isin(int x, int y)
{
    return x >= 1 && x <= n && y >= 1 && y <= m;
}

int dfs(int x, int y, int cnt, int di)
{
    if(fi) return 1;
    vis[x][y] = 1;
    if(cnt > 2) return 0;
    if(cnt == 2 && x - x2 != 0 && y - y2 != 0)    //最重要的剪枝
        return 0;
    for(int i  = 0; i < 4; i++)
    {
        int ans;
        int tempx = x + dir[i][0];
        int tempy = y + dir[i][1];
        if( i == di)
            ans = cnt;
        else
            ans  = cnt + 1;
        if(!isin(tempx, tempy) || vis[tempx][tempy]) continue;
        if(tempx == x2 && tempy == y2 && ans <= 2)
        {
            fi = 1;
            return 1;
        }
        if(!ss[tempx][tempy]){
            if(di == 5) ans = 0;
            if(dfs(tempx, tempy, ans, i))
                return 1;
            else
                vis[tempx][tempy] = 0;
        }
    }
    return 0;
}

int main()
{
    while(cin>>n>>m)
    {
        if(!n && !m) break;
        for(int i = 1; i <= n; i++)
            for(int j = 1; j <= m; j++)
                scanf("%d", &ss[i][j]);
        int q;
        cin>>q;
        for(int i = 0; i < q; i++)
        {
            fi = 0;
            memset(vis, 0, sizeof vis);
            cin>>x1>>y1>>x2>>y2;
            if(ss[x1][y1] == 0 || ss[x2][y2] == 0){
                cout<<"NO"<<endl;
                continue;
            }
            else if(ss[x1][y1] != ss[x2][y2]){
                cout<<"NO"<<endl;
                continue;
            }
            else {
                if(dfs(x1, y1, 0, 5))
                    cout<<"YES"<<endl;
                else
                    cout<<"NO"<<endl;
            }
        }
    }
    return 0;
}

發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章