员工部门工资SQL面试题
现有employee 表,表中有 员工编号(id) 员工年龄(age) 员工工资(salary) 员工部门(deptid), 按要求用一条SQL语句完成
create table employee(
id int identity(1,1) primary key ,
name varchar(50),
salary bigint,
deptid int);
1.查出每个部门高于部门平均工资的员工名单
select ta.* from employee ta,
(select deptid,avg(salary) avgsal from employee group by deptid)tb
where ta.deptid=tb.deptid and ta.salary>tb.avgsal
2、列出各个部门中工资高于本部门的平均工资的员工数和部门号,并按部门号排序。
select ta.deptid,count(*) as ‘人数’ from employee ta,
(select deptid,avg(salary) avgsal from employee group by deptid)tb
where ta.deptid=tb.deptid and ta.salary>tb.avgsal group by ta.deptid order by ta.deptid
3.求每个部门工资不小于6000的人员的平均值;
SELECT avg(salary) as ‘平均值’,deptid FROM employee where salary >=6000 GROUP BY dept_id
4、各部门在各年龄段的平均工资
select deptid,
sum(case when age < 20 then salary else 0 end) / sum(case when age <20 then 1 else 0 end) as “20岁以下平均工资”,
sum(case when age >= 20 and age <40 then salary else 0 end) / sum(case when age >= 20 and age <40 then 1 else 0 end) as “20至40岁平均工资”,
sum(case when age >= 40 then salary else 0 end) / sum(case when age >=40 then 1 else 0 end) as “>40岁及以上平均工资”,
from employee
group by deptid
以上SQL面试题,经常会出现在笔试环节,特别是java开发工程师岗位,虽然并不是很难,但对于那些比较熟悉SSH开发,不经常写SQL的同学来说,有时候还真是不知道怎么写。