《挑战编程》之液晶显示器

 

最近在看老美的一本《挑战编程》，感觉这书挺有意思的，只是没有答案。做了几道，可能是因为开头的几道不算难吧，感觉还算顺利。

 

题目如下，没有翻译，见谅哈

 

1.6.4 LCD Display

PC/UVa IDs: 110104/706, Popularity: A, Success rate: average Level: 1

A friend of yours has just bought a new computer. Before this, the most powerful
machine he ever used was a pocket calculator. He is a little disappointed because he
liked the LCD display of his calculator more than the screen on his new computer! To
make him happy, write a program that prints numbers in LCD display style.

Input
The input file contains several lines, one for each number to be displayed. Each line
contains integers s and n, where n is the number to be displayed (0 ≤ n ≤ 99, 999, 999)
and s is the size in which it shall be displayed (1 ≤ s ≤ 10). The input will be terminated
by a line containing two zeros, which should not be processed.

Output
Print the numbers specified in the input file in an LCD display-style using s “-” signs
for the horizontal segments and s “|” signs for the vertical ones. Each digit occupies
exactly s + 2 columns and 2s + 3 rows. Be sure to fill all the white space occupied by
the digits with blanks, including the last digit. There must be exactly one column of
blanks between two digits.
Output a blank line after each number. You will find an example of each digit in the
sample output below.

 

Sample Input
2 12345
3 67890
0 0

 

Sample Output
……（显示不出来，有点像搜狗的酷字，大家运行一下就知道了）

 

代码如下：

 

#include <stdio.h> #include <stdlib.h> #include <Fatal.h> #define NONE 0 #define FIRST 1 #define MED 2 #define SIDE 3 #define LAST 4 #define VER1 0 #define VER2 1 /*START：挑战编程P14-1.6.4*/ int Num[5][10]={ //全局数组 {MED,NONE,MED,MED,NONE,MED,MED,MED,MED,MED}, {SIDE,FIRST,LAST,LAST,SIDE,FIRST,FIRST,LAST,SIDE,SIDE}, {NONE,NONE,MED,MED,MED,MED,MED,NONE,MED,MED}, {SIDE,FIRST,FIRST,LAST,LAST,LAST,SIDE,LAST,SIDE,LAST}, {MED,NONE,MED,MED,NONE,MED,MED,NONE,MED,MED} }; void OutPut(int,int,int []); int main(void) { int i,j; int width; int A[100]; while(scanf("%d%*c",&width)){ //此处使用%*代替了下面的getchar，意为读入而不存储 //getchar(); if(width==0) break; i=0; while(A[i]=getchar()){ if(A[i]=='/n') break; A[i++]-='0'; }//while for(i=0;i<5;i++){//打印每一行 if(i%2!=0){ for(j=0;j<width;j++) OutPut(i,width+2,A); }//if else OutPut(i,width+2,A); }//for printf("/n"); }//while return EXIT_SUCCESS; } #if VER1 void OutPut(int row,int width,int A[]) { int i,j; int status; char ch1,ch2=' '; if(row%2==0) ch1='-'; else ch1='|'; for(i=0;A[i]!='/n';i++){ status=Num[row][A[i]]; for(j=1;j<=width;j++){ if((j==1&&(status==FIRST||status==SIDE)) ||(j==width&&(status==LAST||status==SIDE)) ||((j!=1)&&(j!=width)&&(status==MED))) putc(ch1,stdout); else putc(ch2,stdout); }//for(j==1) putc(ch2,stdout); }//for printf("/n"); } /*END*/ #endif #if VER2 void OutPut(int row,int width,int A[]) { int i,j; int status; char ch1,ch2=' '; char ch; char Tmp[12]; if(row%2==0) ch1='-'; else ch1='|'; for(i=0;A[i]!='/n';i++){ status=Num[row][A[i]]; status==MED?(ch=ch1):(ch=ch2); for(j=1;j<=width;j++) Tmp[j]=ch; Tmp[j]='/0'; ch==ch1?(ch=ch2):(ch=ch1); if(status!=NONE){ if(status!=LAST) Tmp[1]=ch; if(status!=FIRST) Tmp[width]=ch; }//if printf("%s",&Tmp[1]); putc(ch2,stdout); }//for printf("/n"); } /*END*/ #endif

 

代码中的头文件<Fatal.h>是我自己编写的一个出错处理，该头文件是用宏定义的，打印用户传递的字符串；

定义VER1和VER2是为了使用两个不同的版本，我觉得VER2更好。

不过我觉得，使用全局数组不算是很好的办法，期待更好的办法。