題目鏈接:https://leetcode.com/problems/valid-parentheses/
Given a string containing just the characters ‘(‘, ‘)’, ‘{‘, ‘}’, ‘[’ and ‘]’, determine if the input string is valid.
The brackets must close in the correct order, “()” and “()[]{}” are all valid but “(]” and “([)]” are not.
思路
利用一個棧來保存需要匹配的左括號,碰到右括號則判斷棧頂需要匹配的是不是此類型的括號,最後棧爲空即左括號完全被匹配則爲合法字符串。
class Solution {
public:
bool isValid(string s) {
stack<char> st;
for(auto val:s){
if(val == '(' || val == '{' || val == '[')
st.push(val);
if(val == ')'){
if(st.empty() ||st.top() != '(')
return false;
else st.pop();
}
if(val == '}'){
if(st.empty() || st.top() != '{')
return false;
else st.pop();
}
if(val == ']'){
if(st.empty() || st.top() != '[')
return false;
else st.pop();
}
}
return st.empty();
}
};